Question

Consider the electromagnetic wave shown in the diagram. The wave is propagating through a vacuum along the z-axis. The electric field of the wave is parallel to the y-axis. It is a sine wave of amplitude 15 V/m. The accompanying magnetic field is parallel to the x-axis. See Figure (which is a snapshot at a particular instant) 23 cm 2 6) What is the frequency fof this electromagnetic wave? a.,f= 0.138 GHz b./= 1 .304 GHz c.f 0.652 GHz d.f 0.435 GHz e.f 0.326 GHz How much energy W goes through a square of area 5 m perpendicular to the z-axis (parallel to the xy-plane) in one second? a. W = 1.49 J b. W 0.2 J c. W= 2.11 J d. W- 2.99 J e.W=0.1 J 8) This electromagnetic wave enters a medium with the index of refraction n = 2.55 for this frequency. What is the wavelength, An of the wave in this medium? a.i -234.6 cm b. 117.3 cm ёл.,-4.5 cm d.4,,-18cm

What are the answers and how did you get to the answers?

Answer 1

Lambda = 2 times 23 times 10^-2 = 46 times 10^-2 m. C = 2.99 times 10^8 therefore f = C/lambda = 2.99 times 10^8/46 times 10^-2 = 0.650 times 10^9 Hz f = 0.650 GHz W = P/A = E/t/A = E/At W = 15 v/m/5 times 1 m^2 = 3 J W = 3 J using v = c/n and v = f/lambda lambda_n = C/nf = 3 times 10^8/2.55 times 0.652 times 10^5 lambda_n = 18.04 cm lambda_n = 18 cm