33.
Standard temperature is 15 C at sea level. It decreases 20C per 1,000 ft above sea level, At 1,000', ISA temperature = +15 -2 = + 13
so
at 12,000' pressure height, ISA temperature = +15 -2*12 = - 9
at 4,500' pressure height, ISA temperature = +15 -2 *4.5= + 6
at 24,000' pressure height, ISA temperature = +15 -2*24= - 33
Pressure altitude | Reported Temperature | ISA Temperature | ISA Deviation |
12000 | -3 | -9 | +6 |
4500 | 20 | +6 | +14 |
24000 | -45 | -33 | -12 |
34.
Altimeter reading = 30.33''
Standard reading is 29.92'' at sea level.
so (29.92-30.33)*1000= -410'
So Pressure altitude 7,820-410 = 7,410'
Density altitude = pressure altitude + 120*(Ooutside air temperature - ISA temperature)
Density altitude= 7,410 + 120*( 23 - ( 15 - 2*7.82 ) ) = 10,246.8'
35.
Altimeter reading = 29.80''
Standard reading is 29.92'' at sea level.
so (29.92-29.80)*1000= 120'
So Pressure altitude 6,685 + 120 = 6,805'
Density altitude = pressure altitude + 120*(Ooutside air temperature - ISA temperature)
Density altitude= 6,805 + 120 ( 28 - ( 15 - 2*6.685 ) ) = 9,969.4'
can you please answer all three. thanks Determine the ISA standard atmospheric temperature below, and using...