According to the ideal gas equation we have,
PV = nRT
So, at constant pressure;
V1/T1 = V2/T2
V1 = volume of gas at the temperature T1 (21.6°C = 294.6K)
V2 = volume of gas at the temperature T2
so, 3.62 L/ 294.6K = 3.38 L/ T2
T2 = 275.06K (= 2.06°C)
Hope this helps!
4.) A gas sample is held at constant pressure. The gas occupies 3.62 L of volume...
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Please answer & explain 26-30 A gas sample is held at constant pressure. The gas occupies 3.62 L of volume when the temperature is 21.6°C. Determine the temperature at which the volume of the gas is 3.45 L 26 d) 295 K 309 K b) 281 K c) 20.6 K a) 27. The temperature of a specific amount of gas in a sealed container changes from 20.0°C to 40.0°C. If the volume remains constant, the pressure will change from 755...
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