Question

A sample of oxygen gas occupies 1.9 L at pressure of 1156 torr. What volume will it occupy when the pressure is changed to 912 torr and temperature remains constant?

Answer 1

According to ideal gas equatin

PV = nRT

Here P is presseue, V is Volume, nis mole, R is gas constant, T is temperature

Now if T is constant the nRT term will become constant

So PV = constant

And P1V1 = P2V2

now P1 = 1156 torr V1 = 1.9L

P2 = 912 torr V2 = ??

Put all values

1156 × 1.9 = 912 × V2

V2 = 2.41 L ans.