A sample of oxygen gas occupies 1.9 L at pressure of 1156 torr. What volume will it occupy when the pressure is changed to 912 torr and temperature remains constant?
According to ideal gas equatin
PV = nRT
Here P is presseue, V is Volume, nis mole, R is gas constant, T is temperature
Now if T is constant the nRT term will become constant
So PV = constant
And P1V1 = P2V2
now P1 = 1156 torr V1 = 1.9L
P2 = 912 torr V2 = ??
Put all values
1156 × 1.9 = 912 × V2
V2 = 2.41 L ans.
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