A committee has ten members. There are two members that currently serve as the board's chairman and vice chairman. Each member is equally likely to serve in any of the positions. Two members are randomly selected and assigned to be the new chairman and vice chairman.
What is the probability of randomly selecting the two members who currently hold the positions of chairman and vice chairman and reassigning them to their current positions?
Number of ways of total selections and assignments possible = 10P2 = 10! / (10 - 2)! = 10! / 8! = 90
In this, there will be only one way of randomly selecting the two members who currently hold the positions of chairman and vice chairman and reassigning them to their current positions. Hence,
Required probability = 1/90
A committee has ten members. There are two members that currently serve as the board's chairman...
A committee has nine members. There are three members that currently serve as the board's chairman comma ranking member comma and treasurer. Each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman comma ranking member comma and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman comma ranking member comma and treasurer and reassigning them to their...
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