Question

A committee has ten members. There are two members that currently serve as the​ board's chairman...

A committee has ten members. There are two members that currently serve as the​ board's chairman and vice chairman. Each member is equally likely to serve in any of the positions. Two members are randomly selected and assigned to be the new chairman and vice chairman.

What is the probability of randomly selecting the two members who currently hold the positions of chairman and vice chairman and reassigning them to their current​ positions?

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Answer #1

Number of ways of total selections and assignments possible = 10P2 = 10! / (10 - 2)! = 10! / 8! = 90

In this, there will be only one way of randomly selecting the two members who currently hold the positions of chairman and vice chairman and reassigning them to their current​ positions. Hence,

Required probability = 1/90

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