Question

6) Provide an appropriate response. Round to the nearest hundredth 6) Find the standard deviation for the given probability distribution XP(x) 0 0.19 1 10.26 2 0.18 3 0.24 4 0.13 A) = 1.40 B) c = 1.76 C) = 1.33 D) 0 = 2.28 Find the mean, u, for the binomial distribution which has the stated values of nand p. Round answer to the nearest tenth. 7) n = 1599; p=0.57 A) u = 9057 B) 4 = 913.0 C) 18982 D) u =915.4 8) Provide an appropriate response. 8) Find the area of the shaded region. The graph depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler test). 40 50 60 70 80 90 100 110 160 170 120 130 140 150 A) 0.4400 B) 0.7486 C) 0.8051 D) 0.6293 9) 9) Find the indicated IQ score. The graph depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler test). The shaded area under the curve is 0.10. A) 100,5 B) 119.2 C) 108.1 D) 80.8 Assume that X has a normal distribution, and find the indicated probability. 10) The mean isu - 15.2 and the standard deviation is a 0.9. Find the probability that X is between 14.3 and 16.1. A) 0.6826 B) 0.8413 C) 0.3413 10) D) 0.1587 Solve the problem. 11) A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50. If 40 different applicants are randomly selected, find the probability that their mean is above 215. A) 0,0287 B) 0.1179 C) 0.3821 D) 0.4713 11) A-3

Answer 1

nearest hundredth. the standard deviation for solution in Provide an appropriate response. Round The 6 ind the given Probability Probability distribution х P(X) 0 0.19 0.26 2 0.18 3 0124 4 0.13 we know that Standard deviation (o) = JE&2) - [EX)] Here E(X) = ExP(4) OX0.1 g + 1X0.26 + 2X0.18 + 3x 0124 + 4 X0.13 - 0.26 +0.36 +0,72 +0.52 1.86 11 Now EX)= {Z PIX) 1X0126 + 4X 0118 + 9 X0124 + 16 X0113 0.26 + 0.72 ll + 2.16 + 2.08 5.22 1)

Now JE(+²) - [Ex]]? 9 5:22 3. 46 11.76 1:33 Hence option @ correct. is u. Find the 8+ 7 mean p=0.57) given Xu Binomial ( n=1589, Then u= ne 1589 X0157 905.7 Ang is correct. Hence option Griven 877 XN Normal ( U=100, 5=15) Find The area of Shaded Region. ie. PL x 3 110) 1107400) llo P(x-M Plzs 0.67) 0.7486 Hence option ® is correct.

P(-13291) Þ(1)-061) a $(11-1 = ax 018413 -1 0.6826 Hence option ® is correct. 8+ Griven XN Normal ( 200, 50) and n = 40 Find P ( X > 215) Play in 215- 200 > 50/40 p( 27 Togi 15 = Plz> 10go) 1- PLZS 1.90) = - 1- 0.9713 0.0287 - Hence option ® is correct.