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The combustion of acetylene C2H2, takes place according to the equation: 2C2H2 + 5O2 ---> 4CO2...

The combustion of acetylene C2H2, takes place according to the equation:

2C2H2 + 5O2 ---> 4CO2 + 2H2O; delta H is -5198 kJ

In an experiment, 0.338 g C2H2 is combusted in a bomb calorimeter. If the heat capacity of the calorimeter is 729 J/K and it contains 1/150 kg of water, what is the temperature increase of the bomb calorimeter? The spedicif heat capacity of water is 4/184 J/g.K

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Answer #1

2C2H2(g) 502 (g) 4CO2 (g)2H20(g), H5198 kJ Amount of heat released when 0.338g of acetylene is combusted 5198kJ -0.338g C,H2

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