Provide the type and hexadecimal representation of following instruction: lw $t1, 2($t0)
lw is a J-type format instruction.. lw instruction: ---------------- lw $t, offset($s) 1000 11ss ssst tttt iiii iiii iiii iiii our instruction: ----------------- lw $t1, 2($t0) $t is $t1 => in binary it is 01001 $s is $t0 => in binary it is 01000 offset is 2 => in binary it is 0000 0000 0000 0010 1000 11ss ssst tttt iiii iiii iiii iiii => 1000 1101 0000 1001 0000 0000 0000 0010 In hexadecimal it is 0x8D090002. Answer: 8D090002
Provide the type and hexadecimal representation of following instruction: lw $t1, 2($t0)
For the following instruction, show the binary then hexadecimal representation. sw $t1, 32($t2)
Show all your work, I WILL RATE!! Consider the following code: li $t0, 99 li $t1, 44 loop: addi $t0, $t0, -1 lw $t1, 0($t1) bne $t0, $zero, loop add $v0, $t0, $zero What is the static instruction count of this code? What is the dynamic instruction count? (Assume any pseudoinstructions are counted as 1 instruction). How many times is the instruction memory accessed? How many times is the data memory (i.e. lw/sw) accessed?
Provide the type, assembly language instruction, and binary representation of instruction described by the following MIPS fields: op = 0, rs = 10, rt= 15, rd = 22, shamt = 0, function = 36
MULTIPLE CHOICE!! If register t0 contains 0 and t1 contains 4, what would the following instruction do? (MIPS) sw $t0, 0($t1) A. Load 4 into register t0 B. Load 0 into register t1 C. Copy the content at memory address, 4, into register t0. D. Copy the contents at memory address, 0, into register t1. E. Copy the contents of register t0 into the memory address, 4. F. Copy the contents of register t1 into the memory address, 0.
Given the big-endian instruction memory map shown below in (b), and the initial values $t1 0XE7eeeADD, $s5 = 0x80000010 . We execute the following instructions: lw $t1, 12($s5) andi $t1, $t1, 0x3E0000A9 sra $s5, $s5, 3 addi $se, $s5, 2 sw $t1, -4($s0) Answer the following questions: (a) What values are contained in $se and sti after executing the above instructions? Write your answers in Hex format. Given the big-endian instruction memory map shown below in (b), and the initial...
4. Study the following example, and determine the addressing mode used in each instruction: .data Arr: .word 10 .word 20 .text globl main main la $s0, Arr lw $t0, 0(Ss0) lw St1, 4(Ss0) add St2, $t0, $t1 addi $t2, $t2, 1 sll $t2, $t2, 1 4. Study the following example, and determine the addressing mode used in each instruction: .data Arr: .word 10 .word 20 .text globl main main la $s0, Arr lw $t0, 0(Ss0) lw St1, 4(Ss0) add St2,...
2.17 [51<82.5> Provide the type, assembly language instruction, and binary representation of instruction described by the following MIPS fields: rt-8 , Just looking at the fields provided, what's the instruction op-0x23, rs-16, const-0x25F0 a. format? R-type_I-typeJ-type b. What's the instruction? In which register is the base address stored? What value will be added to that base address (in decimal): In which register will the result be stored? c. d. e.
4. (3 pts. each) Write the hexadecimal representation of each MIPS assembly instruction: (4.1) sub $s3, $t1, $s2 (4.2) bne $t3, $t4, 18 (4.3) sll $s0, $t5, 2 5. (20 pts.) Consider the following C (or java) code: else f=f+2; By storing the value of j in Ss0, write a sequence of MIPS assembly instructions that will execute these lines of code for the following two cases: (5.1) assuming that the values of f, g and h are stored in...
Compiling C Programs into MIPS Assembly and Machine Code sll $t1, $a1, 2 add $t1, $a0. $t1 lw $t0, 0($t1) lw $t2, 4($t1) sw $t2, 0($t1) sw $t0, 4($t1) 1. From the assembly code, what machine code might a MIPS assembler produce? 2. What does this program do? Write the C code for this assembly program.
Consider the following MIPS machine code. bne $0, $0, 2 addi $t0, $0, 5 addi $t1, $0, 10 What will be in $t0 and $t1 after the above program is executed? a. $t0 = 5, $t1 is unknown because 3rd statement will not be executed b. $t1 = 10, $t0 is unknown because 2nd statement will not be executed c. $t0 = 5, $t1 = 10 d. $t0 = 0, $t1 = 0