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12 - 14: Consider three unlinked genes: a, b, c are the recessive alleles, and A, B, C are the dominant alleles. Now if two t
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12. - (b) 1/64 = 0.0156 lsbablity of getting a single recessive gene=1/4 for each. ie. XX XX X X xx Out of 4 only 1 is recessNote :- comment for the further assistance and give thumbs up

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