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In chicken, comb shape is determined by non-epistatic interaction between two loci (R,r and P,p)
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In chickens, comb shape is determined by non-epistatic interactions between genes at two loci (R, r...
In chickens, comb shape is determined by alleles at two loci. A walnut comb is produced...
In chickens, comb shape is determined by alleles at two loci. A walnut comb is produced when at least one dominant allele A is present at one locus and at least one dominant allele B is present at the second locus. A rose comb is produced when at least one dominant allele is present at the “A-locus” and two recessive alleles are present at the “B-locus”. A pea comb is produced when two recessive alleles are present at the “A-locus”...
Question 3 1 pts The color of chickens is determined by gene B, such that BB=black,...
Question 3 1 pts The color of chickens is determined by gene B, such that BB=black, Bb = gray, and bb = white. A second gene R controls comb shape, with dominant rose and recessive single comb. If a white single-combed chicken is mated with a gray chicken that is heterozygous for rose comb, what fraction of the offspring will be gray with rose comb? 1/4 9/16 1/8 O 3/8 1/16
Chapter 4: Extensions of Mendelian Inheritance Help Seve & You cross a rose comb chicken with...
Chapter 4: Extensions of Mendelian Inheritance Help Seve & You cross a rose comb chicken with a peacomb chicken and get all walnut comb progeny. You then cross two of the walnut combed chickens from the F1 generation and get 9 walnut combs: 3 rose combus:3pea combs : 1 single comb. Which of the following would best explain these results? Underline means any allele could be present. For example R could be RR or Rr Skoped Rose comb Pea comb...
PRE-LAB QUESTIONS - Genetics - Lab #9 1. Humans inherit two alleles for every gene. For...
PRE-LAB QUESTIONS - Genetics - Lab #9 1. Humans inherit two alleles for every gene. For an example, gene "R" provides the instructions for face shape. The dominant allele for the gene is denoted as R and the recessive allele for the gene is denoted as r. The dominant phenotype is a round face shape and the recessive phenotype is a square face shape. Use this information to answer the questions below: What is the genotype of a homozygous dominant...
Question 25 2 pts In dragons, the dominant allele R causes solid tail color, and the...
Question 25 2 pts In dragons, the dominant allele R causes solid tail color, and the recessive alleler results in white spots on a colored background. The black coat color allele Bis dominant to the brown allele b, but these genes can only be expressed if the animal has an mm genotype at a third gene locus. Animals that are M are yellow regardless of which allele from the Blocus is present. A mating between a solid yellow-tailed male dragon...
1) Coat color in mice is determined by several independently assorting autosomal genes. Gene A is...
1) Coat color in mice is determined by several independently assorting autosomal genes. Gene A is involved in the distribution of pigment along the hair. A dominant allele (A) produces a hair color called "agouti"--the hair has dark pigment at the base and tip of each hair shaft and yellow pigment in the central portion of the shaft. Homozygous recessive mice (aa) are missing the yellow stripe and thus have solid dark-colored hair. Gene B is involved in the color...
Question 12 only. Punnett's square analysis for the parental cross r Rr Rr 9) If we...
Question 12 only.
Punnett's square analysis for the parental cross r Rr Rr 9) If we used the above offspring (F1) in a new cross, what would be the genotypes and phenotypes of the offspring of the Fz generation? 10) What is the genotypic ratio of the F2 generation? 11) What is the phenotypic ratio of the F2 generation? 12) What would be the genotypic and phenotypic ratios of offspring from a cross between a homozygous recessive parent (r r)...
Question 7 1 pts Two genes controlling scale coloration (B) and scale shape (R) in crested...
Question 7 1 pts Two genes controlling scale coloration (B) and scale shape (R) in crested geckos are 16 CM apart on the same autosome. Brown (B) is dominant to yellow (b) and round (R) is dominant to angled (r). A brown, round-scaled individual with the allelic configuration Br/bR is crossed with a br/br individual 50 offspring are produced. How many of those offspring do you expect to be brown with round scales? O 34 17 LOO 08 42
In mice, genes for albinism (a), chronic, inflammation (i), and reduced sense of smell (r) are...
In mice, genes for albinism (a), chronic, inflammation (i), and reduced sense of smell (r) are linked. You initially crossed a mouse that is homozygous dominant for all three traits with a mouse that is homozygous recessive for all three traits. You then crossed several of the resulting F_1 offspring to mice that are homozygous recessive for all three traits. You observe the following phenotypes in the offspring: Diagram a map between the genes and calculate the map distances. If...
Assume that tail length in mice is a quantitative trait involving two genes, each with 2...
Assume that tail length in mice is a quantitative trait involving two genes, each with 2 alleles. One allele at each gene contributes to long tails, the other allele at each gene does not (small tails). The genes are located on different autosomes. Mice with 0 contributing alleles have tails that are 4 cm in length; mice with tails with 4 contributing alleles are 12 cm in length. Determine the phenotypic ratio from an F2 from a true breeding parent...
Question 3 1 pts The color of chickens is determined by gene B, such that BB=black, Bb = gray, and bb = white. A second gene R controls comb shape, with dominant rose and recessive single comb. If a white single-combed chicken is mated with a gray chicken that is heterozygous for rose comb, what fraction of the offspring will be gray with rose comb? 1/4 9/16 1/8 O 3/8 1/16
Chapter 4: Extensions of Mendelian Inheritance Help Seve & You cross a rose comb chicken with a peacomb chicken and get all walnut comb progeny. You then cross two of the walnut combed chickens from the F1 generation and get 9 walnut combs: 3 rose combus:3pea combs : 1 single comb. Which of the following would best explain these results? Underline means any allele could be present. For example R could be RR or Rr Skoped Rose comb Pea comb...
PRE-LAB QUESTIONS - Genetics - Lab #9 1. Humans inherit two alleles for every gene. For an example, gene "R" provides the instructions for face shape. The dominant allele for the gene is denoted as R and the recessive allele for the gene is denoted as r. The dominant phenotype is a round face shape and the recessive phenotype is a square face shape. Use this information to answer the questions below: What is the genotype of a homozygous dominant...
Question 25 2 pts In dragons, the dominant allele R causes solid tail color, and the recessive alleler results in white spots on a colored background. The black coat color allele Bis dominant to the brown allele b, but these genes can only be expressed if the animal has an mm genotype at a third gene locus. Animals that are M are yellow regardless of which allele from the Blocus is present. A mating between a solid yellow-tailed male dragon...
Question 12 only.
Punnett's square analysis for the parental cross r Rr Rr 9) If we used the above offspring (F1) in a new cross, what would be the genotypes and phenotypes of the offspring of the Fz generation? 10) What is the genotypic ratio of the F2 generation? 11) What is the phenotypic ratio of the F2 generation? 12) What would be the genotypic and phenotypic ratios of offspring from a cross between a homozygous recessive parent (r r)...
Question 7 1 pts Two genes controlling scale coloration (B) and scale shape (R) in crested geckos are 16 CM apart on the same autosome. Brown (B) is dominant to yellow (b) and round (R) is dominant to angled (r). A brown, round-scaled individual with the allelic configuration Br/bR is crossed with a br/br individual 50 offspring are produced. How many of those offspring do you expect to be brown with round scales? O 34 17 LOO 08 42
In mice, genes for albinism (a), chronic, inflammation (i), and reduced sense of smell (r) are linked. You initially crossed a mouse that is homozygous dominant for all three traits with a mouse that is homozygous recessive for all three traits. You then crossed several of the resulting F_1 offspring to mice that are homozygous recessive for all three traits. You observe the following phenotypes in the offspring: Diagram a map between the genes and calculate the map distances. If...
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