Homework Answers
4) Given in a Induction Motor
V2 = 460 volts
Stator frequency, f = 50 Hz.
Poles = 2
Slip = 5% = 0.05.
Ns = 120f / P = (120 ) (50 ) / 2 = 3000 RPM = Sychronous frequency.
also given, friction and windage losses (or) mechanical losses
Pme = 700 w.
core losses = 600 w.
(a) Shaft speed in RPM.
Shaft speed (or) Rotor speed, Nr = Ns ( 1 - s)
= 3000 ( 1 - 0.04 )
Nr = 2850 RPM
(b) Output power in horse power.
we have , 1 British horse Power = 0.746 kw.
1 Metric horse Power = 0.785 kw (mostly preferred)
Out put power , point = 50 kw
= 50 / 0.735
Pout = 68 HP
in MHP
Out put power , point = 50 kw
Pout = 50/ 0.746
Pout = 67 HP in BHP.
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