Two flies that are heterozygous for the recessive traits yellow body color and singed bristles are...
Two flies that are heterozygous for the recessive traits yellow body color and singed bristles are crossed. Their progeny is as follows: 215 Yellow body, 185 Singed bristles, 67 Wild type, and 33 Yellow body Singed bristles. Calculate the map distance in cM.
Homework Answers
Given:
215 Yellow body
185 Singed bristles
67 Wild type
33 Yellow body Singed bristles
The progeny which are not similar to parents are considered as recombinant and their frequency is used to calculate the recombination frequency. The frequency of progeny which are similar to their parents is not used.
recombination frequency in centimorgan using the formula: [(67+33)/(67+33+215+185)] x 100% = 20%
and
1 percent recombination frequency is represented by 1 cM.
so, 20% 
20 cM
therefore, the map distance for the recombination is 20 cM.
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