Question

Balance the following chemical equation and determine the number of moles of Fe(s) produced when 0.75 moles of Fe_2O_3 (s) react with excess C(s) to produce Fe(s) and CO_2(g). Multiple Choice 1.50 moles 0.75 moles 3.50 moles 4.50 moles Submit

Answer 1

2Fe₂O₃(s) + 3C(s) --------------> 4Fe(s) + 3CO₂ (g)

First balance the number of oxygens multiplying by 3 x CO2 and 2 x Fe₂O₃ followed by carbon and Fe in the last step.

2Fe₂O₃(s) + 3C(s) --------------> 4Fe(s) + 3CO₂ (g)

Stoichiometrically, 2 mol 3 mol 4 mol 3 mol

2 moles of Fe₂O₃ react with excess C to produce 4 moles of Fe

1 mole of Fe₂O₃ reacts with excess C to produce 4/2=2 moles of Fe

0.75 moles of Fe₂O₃ react with excess C to produce 2*0.75= 1.50 moles of Fe

Answer is A

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