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A : 16. A pendulum oscillates back and forth until it stops due to friction (graph at right). What is the period and decay time of this motion? a. T=0.80(S), T=0.20(s) b. T= 1.25(S), 1=5.0(s) c. T=0.80(S), t=5.0(s) d. T= 1.25(S), T=0.20(S) e. T=5.0(S), T=1.25(S) EXPLAIN YOUR ANSWER. Damped Amplitude (m) 3 -0.5 0 2 4 6 time (s) 8 10

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1.0 O 0. 5 .4 0.0 E -0.5 0 2 4 56 8 10 time (s) Time constant τ is the time taken by object to decreases its amplitude from m1m 2.7 Y =-= 0.37m = 0.4 m So, from figure, we can see, Y = 0.4m is at time = 5sec. So, time constant= τ 5 sec1.0 0.5 0.0 -0.5 1 .25 0 2 4 6 8 10 time (s) From figure, att 1.25 s, it completes its one oscillation Time period = T = 1.25

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