Question

As shown below, a square loop of wire of side a moves through a uniform magnetic field of magnitude B perpendicular to the page at constant velocity V rightarrow directed to the right. Which statement regarding the electric field induced in the wires is correct for the wires at the left and right sides of the loop? The electric field is directed upwards in both the right and left sides of the loop. The electric field is directed upwards in the right side and downwards in the left side of the loop. The electric field is directed upwards in the left side and downwards in the right side of the loop. The electric field is directed downwards in both the right and left sides of the loop. There is no electric field present in any side of the loop.

A. The electric field is directed upwards in both the right and left sides of the loop.
B. The electric field is directed upwards in the right side and downwards in the left side of
the loop.
C. The electric field is directed upwards in the left side and downwards in the right side of
the loop.
D. The electric field is directed downwards in both the right and left sides of the loop.
E. There is no electric field present in any side of the loop.

Answer 1

E. There is no electric field present in any side of the loop.

induced emf = d $\phi$ / dt ..

$\phi$ = B .A.. here dB/dt = 0 and dA/dt = 0 as with time there is no change in magnetic field or the area as velocity is constant..

so induced emf = d $\phi$ / dt = 0.. so no electric field