Question

CH(CH),CH) will react with gaseous oxypen (0) to produce gaseous carbon dioxide (C0.) and gaseous water (H,0). Suppose 41.9 Gaseous butane of butane is mixed with 59.7 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 3 significant digits. 5 ?

Answer 1

2C4H10 + 13O2 = 8CO2 + 10H2O

number of moles of butane = 41/58 = 0.71 moles

number of moles of oxygen = 59.7/32 = 1.86 moles

for 1 mole of butane we need 5.5 moles of oxygen

1.86/5.5 = 0.34

we have only enough oxygen to react with 0.34 moles of butane

oxygen is the limiting reagent

number of moles of CO2 = 4 x 0.34 = 1.36 moles

mass of CO2 =1.36 x 44 =59.84 g