In a 25 T magnetic field directed vertically upward, a particle having a charge of magnitude...
In a 25 T magnetic field directed vertically upward, a particle having a charge of magnitude 9.00 microC and initially moving northward at 6.4 km/s is deflected toward the east. Calculate the magnitude of the magnetic force on the particle in N.
Homework Answers
Here ,
B = 25 T
q = 9 uC
v = 6400 m/s
Here ,
magnetic force = Bvq
F = 25 * 9*10^-6 * 6400
F = 1.35 N
the magnetic force acting on the particle is 1.35 N
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