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When writing open contrary you Wed filled sublev
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Mg(12) = 1s2 2s2 2p6 3s2

Hence the last element enters into 3s2 orbital

Dy(66) = [Xe] 4f10 6s2

Hence the last element enters into 4f orbital

Cl(17) = 1s2 2s2 2p6 3s2 3p5

Hence the last element enters into 3p orbital

K(19) = 1s2 2s2 2p6 3s2 3p6 4s1

Hence the last element enters into 4s orbital

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