Question

Please show work.

22. A ladybug is accelerating when flying around a circular path of radius r. The velocity vectors of the ladybug the ladybug 1.31s to move from point A to point B, what is the magnitude of her tangential acceleration? points A and B as shown in the picture. If it takes are measured at m m = -3.25-î + 3.25 S B m 4.50 Δθ450 S A a) at = 0.0734 m/s2 b) at = 0.954 m/s2 c) a, = 1.53 m/s2 d) a, = 2.70 m/s2

Answer 1

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V^rightarrow_A = 4.50 m/s J V^rightarrow_B = -3.25 m/s i + 3.25 m/s J Vertical-bar V^rightarrow_A Vertical-bar = 4.5 m/s Vertical-bar v^rightarrow_B Vertical-bar = squareroot (3.25)^2 + (3.25)^2 3.25 squareroot 2 4.59 m/s It takes time 1.31 seconds from A to B so tangential acceleration (a_t) = (a_t) = Vertical-bar V^rightarrow_B Vertical-bar - Vertical-bar V^rightarrow_A Vertical-bar /At rightdoublearrow a_t = 4.595 - 4.5/1.31 = 0.095/1.31 a_t = 0.0729 m/s^2 a_t = 0.073 m/s^2