Question

1. Assuming our label 'a' is to be an array of 32bit integers, the following code...

1.

Assuming our label 'a' is to be an array of 32bit integers, the following code creates an array of how many elements?

.data     
.balign 4  
a: .skip 600
150
140
75
300

None of the above

2.  

Assuming the variables: x, y, and z are already defined as integers with x=6, y=4, and z=12, which of the following printf statements written in C/C++ will correctly output the following to the terminal screen:

Point(6,4,12)

printf("Point(%d,%d,%d)",x,y,z);
printf("Point(%d,%d,%d)",z,y,x);
printf("Point(%d,%d,%d)",x,y);
printf(x,y,z,"Point(%d,%d,%d)");
0 0
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Answer #1

1. 150

balign advances the location counter to 4's multiple. Hence 600/4 = 150

2.

printf("Point(%d,%d,%d)",x,y,z);

While using printf(), we should first use the format specifier, here %d then use variable to print.


answered by: ANURANJAN SARSAM
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