Question

Q1 (10 points): Consider the two stress-strain curves shown to the right. Based on each of these stress-strain curves, calculate or identify the following items: (a) • Modulus of elasticity Yield stress Yield strain Ultimate stress Ultimate strain Fracture stress Fracture strain • Ductility ratio Modulus of resilience Modulus of toughness u oo Stress (ksi) Straini 0.0012 0.0031 0.0039 0.0064 0.0079 O Note: If any of the values you need to identify or calculate are not explicitly clear from the stress-strain curves, you may need to estimate those values. If you utilize any estimations, state any assumptions that are made when making that estimation and justify why that estimation or assumption is reasonable. Stress (ksi) Straini 0 0.001 0.002 0.003 0.004 0.005

Answer 1

Answer :

The two strek Shrain Cuwe shown in the question ----- - - -- 39 ---- 31 --- - Stress Oksi) 0.0012 0-0031 00037 0.0064 0.0079 We have to calculate the follockung based on each of these $10.35 -- Sison Cupves (0) Modulell of lastialy - E Stress strain : o 39 n = 32500 Ksi (Mi) jeild kain = 0-699 ksi (h) yeild so = 39ksi - IV) (ultimate stress - U16 ksi 0.0079 () ultimate Sliain (17) Fractuine strets (vii) Fracture Strain : Hoksi 0.0049 (vill) Modules of Resilience - l = 5 0.0012 + 39 ) - 0.0234 KSI Par Duebut uato 0-0039 0.003) = 10258

(c) Modules of toughness Her Y 0.0012 ¥39+ (0-0031 - 00012 ) * 34 - C000290.0031)x39 + ** (40-39) (0.0039–0·003)) i (16-31 Ders (0.0064-6-0039 ) + Co.00u - 0.0094). 31 + 5* (uo. 31) (0.0019 -0.0064 ) + 10.0019 -0.0064) 31 0.2396 ksi 24 --- 18 A 020-00 0.00 0.00 0.00 0.005 = 30x109 ksi 19) Modules of elasticity E= 24 ** ආපදා (ii) yella stress - 28ksi (113) yold stain • 0.001 ultimate 125 - 32 ksi (v) Ultimate stain = 0.0018

(vi) Fuatre stress - 22 ksi (vii) Fnature stan 0-0048 teetility ratro : 0-002 0.0012 ixy Modules of Resillen l la = 12 * 2.4 * 0-000$ 0.0096 ksi (X) Modulus of toughness 250.001 +6 = 0.15 ksi Capproximately