Question

Problem No. 2 (Figure 2) (ksi) Figure 2. Upper scale Lower scale The stress-strain diagram of a mild-steel specimen is shown in the figure. The specimen has a diameter of 0.50-inch and gage length of 2-inch. Determine the following: (a) yield strength (oy); (b) ultimate strength (out); (c) Young's modulus (E); (d) modulus of resilience; (e) if the specimen is loaded to 105 ksi and then unloaded completely, determine the permanent increase in the gage length € (in/in) 0 0.04 0.08 0.12 0.16 0.20 0.24 0.28 0 0.0005 0.001 0.0015 0.002 0.0025 0.003 0.0035

Answer 1

length = a inch Given clater Stress-strain diagram - drametes = 0.5 inch gage To find: (a) yield strength (Oy) : (6) Ultimate strength (c) Young's Mortutes (E) (a) Permanent increase in gage length

Solution: (6) Yield strength (Oy): S he is the point at which material changes E from elastic region to plastic region. E from the diagram, 10g = 60 kai Come) : | (6) Vermate Tensile strength (Out) I from the diagram, it is the highest point that I the material can be loaded. F Our = 110 ksi (Am) (0) Young's Modulas (E); o 30 TE = 60,000 ksi] = to x63 Rai | (a) Permanent increase in gage leng, the - O= log lest Cayler & cinlerding) 1. This can be done by plotting a line parallel to slope from the wo esi point. $ 0.0P - 0.00175= 0.01%25 inlin Permanent increase = 0.0182802 I Permanent Storgation = 0.1565 in Cams)