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2. The output current of a half-wave rectifier is a sinusoidal variation with the negative half cycle chopped off. If the max

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2. The unveform of the current as described in the question can be shown as ut enn 011 {m- looma ; f= 6042 Ru= 10002 → The av→ L () EN = Iv: Iny = looma = soma. The power dissipated in an Resistor of 1000 is given by P= Its = (50X163)*x 1000 - 2500x

answered by: ANURANJAN SARSAM
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