Question

is 다. Firing Circuit

A single phase half wave controlled rectifier shown below operates from ideal sinusoidal source with vi =325sinwt at 50Hz. If the load is purely resistive, and at a certain α, the output dc voltage is Vdc =95V, and the average valu of the load current is 2.2A. It is required to calculate the following:

a)     The triggering angle α

b)     Load resistance

c)     r.m.s load current

d)      dc power

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Answer #1

Vi = 325 sinot 50 HZ 나 Here Vm = 325V m Vdc = 95v Idc 2,2A that we know um (1+60sa) Vdc 2a 95 - 335 (itcosa) aa 10836 = It co© we know that Ras load current (Irms) I Vm 10 Rms That Sinza ara 2 R. 325 こ T-33.2lxa 180 +sin (2x33:21) 27 2 43.18 Irms = 3

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