Be sure to answer all parts.The equilibrium constant (K) for the formation of nitrosyl chloride, an...
Be sure to answer all parts.The equilibrium constant (K) for the formation of nitrosyl chloride, an orange-yellow compound, from nitric oxide and molecular chlorine 2NO(g)+Cl2(g)= 2NOCI(g) is 5 x 105 at a certain temperature. In an experiment, 8.90 x 10 and 3.30 moles of NOCI are mixed in a 3.00-L flask mole of NO, 1.80 x 103 mole of Cl), What is Qe for the experiment? (Enter your answer in scientific notation.) x 10 In which direction will the system...
The equilibrium constant, K, for the formation of nitrosyl chloride from nitric oxide and chlorine. 2NO(g) + Cl2(8) = 2NOCI(g) is 6.5 x 104 at 35°C. In which direction will the reaction proceed to reach equilibrium if the starting concentrations of NO, Cl., and NOCI are 2.6 x 10-3 M, 7.4 x 10-M, and 5.8 M respectively? o o O shift right shift lent neither
Nitrosyl chloride, NOCI, decomposes to form nitrogen monoxide gas and chlorine gas according to 2NOCI(g) = 2NO(g) + Cl2(g) Assuming that we start with no moles of NOCI(g) and no NO(g) or Cl2(g), derive an expression for K, in terms of the equilibrium value of the extent of reaction, Šeg, and the pressure p. Given that Ky = 2.00 x 10-4, calculate Šeg/no, when p = 0.080 bar. What is the new value of Šeg/no at equilibrium when p =...
Use the data below to calculate AG for the decomposition of nitrosyl chloride at 25°C when the partial pressures are 5.00 atm of NOCI 1.00 x 10-3 atm of NO, and 1.00 x 10-3 atm of Cl, 2NO(g) + Cl2(g) + 2NOCI(g) Substance and State AG: (kJ/mol) Cl(8) 0 NO(g) 87.6 NOCI(8) 66.1 Express your answer in kilojoules per mole to one decimal place. ΠΠΙ ΑΣΦ AG= kJ/mol Submit Request Answer
63. At 35°C, K = 1.6 x 10-6 for the reaction 2NOCI(9) = 2NO(g) + Cl2 (9) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 2.0 moles of pure NOCI in a 2.0-L flask Answer b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask Answer c. 2.0 moles of NOCI and 1.0 mole of Cl, in a 1.0-L flask
14. For the reaction: 2NOCI(g) 2NO(g) + Club), K = 1.6 x 10. What are the equilibrium concentrations of each species it tions of each species if 1.0 mole of NOCI is initially placed in an empty 2.0 L flask? 14. For the reaction: 2NOCI(B) = 2NO(g) + Cl2(g), K = X 1.6*10 What are the equilibrium concentrations of each species if 1.0 mole of NOCI is initially placed in an empty 2.0 L flask?
Part A Use the data below to calculate AG for the decomposition of nitrosyl chloride at 25°C when the partial pressures are 5.00 atm of NOCI, 1.00 x 10-3 atm of NO, and 1.00 x 10-3 atm of Cl2. 2NO(g) + Cl2(g) + 2NOCI(8) Substance and State AG°f (kJ/mol) Cl2(g) 0 NO(g) 87.6 NOCI(g) 66.1 Express your answer in kilojoules per mole to one decimal place. VO ΑΣΦ ? AG = kJ/mol Submit Previous Answers Request Answer
Nitric oxide (NO) reacts with chlorine gas (Cl) to form nitrosyl chloride (NOC) according to the reaction below: 2 NO(g) + C12()=2 NOCI(g) Kp = ? at 700 K A rigid vessel initially contains equimolar amounts of NO and C1, (and nothing else) at 700 K and a total pressure of 2.00 bar. After the system reaches equilibrium at 700 K, the total pressure is found to be 1.84 bar. What is the value of the equilibrium constant Kp? A)...
REVIEWS (References At a particular temperature, K = 7.9 x 10-7 for the following balanced reaction: 2NOCI(g) + 2NO(9) + Cl (9) In an experiment in which 2.5 mol of NOCI is placed in a 4.0-L vessel, what are the equilibrium concentrations of all gases? [NOCI [NO] = Cl2] = Submit Answer Retry Entire Group 5 more group attempts remaining
Calculate the free energy AG at 25°C for the nonstandard conditions at point where the reaction quotient Q is 2.75 x 10 Express your answer numerically in kilojoules. View Available Hint(s) % ALC O ? AG - CO Nitrosyl chloride formation Chlorine gas. Cl(s), reacts with nitric oxide, NO(), to form nitrosyl chloride, NOCI(g), via the reaction Cl(s) + 2NO(g) + 2NOCI() The thermodynamic data for the reactants and products in the reaction are given in the following table: Substance...