When we represent the values of nodes of the binary tree T in the form of an array.
We know that, any node present at the position 'i' in the index has :
Left child at position = 2i+1 and
Right child at position = 2i+2
Therefore, for every i in the array, we just need to get the maximum of the value present at '2i+1' and '2i+2'.
This will get you the answer in linear time.
ALGORITHM:
for i = 0:sizeof(x)
if( 2i+2 <= sizeof(x) )
temp = max( x[2i+1] , x[2i+2] )
else
temp = -1
z[i] = temp
return z
8. You are given a binary tree T (V,E) with a designated root node. In addition,...
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