Question

9 A student in a laboratory uses the apparatus shown in the figure to determine the specific heat capacity of aluminum to low voltage supply and measuring instruments thermometer electrical heater The readings obtained in the experiment are given be Mass of aluminum block = 930 g The initial temperature of block = 13.1 °C The final temperature of block = 314.3 K Electrical energy supplied = 23 800) aluminium block (a) Use the above readings to calculate the specific heat capacity of aluminum. (2 marks) (b) If a student use aluminum block has a mass of 2.00 kg. Which you would expect to have higher heat capacity, aluminum of 930 g or aluminum of 2.00 kg? Explain (1 mark) (c) Centigrade and Fahrenheit thermometer are immersed in a fluid in which the Fahrenheit reading is thrice that of the centigrade reading. What are the absolute values of temperature in Kelvin? (2 marks)

Answer 1

- mass of aluminum= 930g (Til initial temperature = 13.j°C (Ts) final temperature = 314.3k Energy supplied = 23 800 5 Ty(e) C = K-273 es temp in C P K-temp in Kelvin Tp (C)= (314-3 -273345 To (c) = 41.3°C a) We know a zmcat 1 (m-mars) (E-energy), (BT-change in temp) C-specific heat capacity → 23000 = .93xCX(01.3-1311) 5 C = 23000 93 x 20.2 [c= 907.5 J kgl oct b) Heat required to raise the temp of 2 kg of aluminum *907.5x (413-13.1) = 51103J S1103 2101551°C 41.3-13.1² Heat capacity (930g) = 23000 = 243.9751°C 1 Therefore 2kg of aluminum have more heat capacity then 930g of aluminum . Hence more mass will have more heat - capacity.

g c) the conversion famula for tempe - F-32, kr 273 у не даез Fe3e =) = 36-32 -> C = 26.67°c K= 273 +C = K = 273+ 26:67 - K= 299.67°k