A picture P of weight W = 60.0 N is hung by two strings as shown....

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A picture P of weight W = 60.0 N is hung by two strings as shown. The magnitude of the tension force of each string T is 70.0 N. The angle θ is:

Answer 1

Answer #1

Given :

W = 60 N

T = 70 N

The vertical component of the Tension in the both strings together balances weight of the Body.

that is, $2Tsin\theta = W$

$\Rightarrow sin\theta = \frac{W}{2T}$

$\Rightarrow sin\theta = \frac{60}{2*70} = 0.428$

$\Rightarrow \theta = sin^{-1} (0.428) = 25.34^{o}$ [answer]

Answer 2

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