Question

in a c# program I am trying to allow the area to be divided by a set choice.

the area is set as an int in another method and I am unable to call it into the method I need it in.

Is there a way to call Int?

I also need to set each case to have an integer value. For example if they select 1 it is set at a value of 5.

This is what I have so far.

public static void Main(string[] arg)

{

int area;

area = length * width;

}

//I do have Opt(area); to try and call upon the area but it doesn't like that it is an int and not a string. but it will not compile.

int choice = -1;

while(choice != 0 )

{

OptionMenu();

choice = convert.ToInt32(Console.readLIne());

Opt(choice);

Console.readKey();

]

public static void Opt(int Choice)
{

  
   switch (Choice)
{
  
  
  
case 1:

\\this is where I need to call upon the area.

\\and need the choice set to a value

\\ basically I need the area divided by their choice which is set at a value to be computed and then displayed.
Console.WriteLine("\n You selected " + area/ choice + "in your box!"); ;
break;

}

Answer 1

Program in c#

You can use the following function to achieve your program objective

//function header. pass the value of area too
public static void Opt(int Choice,int area)
{
    switch(Choice)
    {
        case 1:
            //set the value of choice as desired
            choice=5;
            //here you will divide the area by the choice set by you
            Console.WriteLine("\n You selected " + area/ choice + "in your box!"); ;
            break;
        //specify the other case
    }
}