Question

Full Name Dis Sec. Day/Time Forces Which of the following series of compounds is listed in serms of insreasing intermolecular forces decreasing vapor pressure, increasing boiling point and freezing point NaCl CCl. Ar A) NaCI> CCl. HOA D) HO>NaCI> Ar > CCL 2 Circle the species having the smallest (Gowest) value of the property listed A) Viscous B) Intermolecular Forces C) Vapor Pressure CCL H,0 D) Freezing Point E) Solubility in WaterCH, Cl CH CH CH CH CH,OH 3. Which of the following compounds is expected to have the HICHEST boiling poin? A) CH,OCH B) CH,CH OH C) CH,CH,CH,CH, D) CHCHCH, 4 Which of the following compounds is expected to have the HIGHEST melting point? A) CH,OCH B) CH,CH OH C) CH,CH,CH,CH D) CH,CH,CH 5. Using your knowiedge of intermolecular forces, explain why the boiling points of 12 (184 C), Br (60 C) G, (-35 . C) and F2(-188" C) follow this trend.

Answer 1

NaCl CCl_4 H_2O Ar electrostatic force dispersion force H-bonding dispersion rightarrow NaCl > H_2 O > CCL_4 > Ar by comparing surface area surface area force \r\n C_20 H_41 On H bonding uparrow but more no of carbon downarrow the H-bonding Therefore viscosity also downarrow Cl_2 rightarrow less surface area rightarrow less force I_2 rightarrow more surface area rightarrow more intermolecular force rightarrow less pressure rightarrow N_2 rightarrow surface are rightarrow less inter molecular force rightarrow low freezing point CH_3 CH_2 CH_3 rightarrow No H - bonding solubility downarrow \r\n Highest B P implies more H-bonding which is possible only in (B) Sane as force of attraction uparrow melting point 1 increase due H-bonding in CH_3 CH_2-OH its melting point is highest As surface area uparrow force of attraction uparrow Therefore B, P uparrow I_2 rightarrow due to large of size of I atom, its surface area is highest therefore B P also highest