Question

#6. (10 points) Using Jones vectors and matrices: Suppose right-circularly polarized light is incident on a quarter wave plate with fast axis at an angle to the x-axis. Show that the output is linearly polarized and find the polarization angle.

Answer 1

O Solleffen - In this using Jones vectors and rratdikes 5) we have to show that the oud peed is limearly polarized and find the polarization angle - the Jones vector of the left part of arcululls polarized light is given. 12>= 12 ()->0 . =) then the Jones matrix of a quater waveplate with the fast of axis of the angle at the x-axis si root isino [!-) sind cost Aowp10) = 0 + (c-tj.Sino cose sino + 1885 g - then the output Tu = Homp (8) 23 - tos I elt)ces*o+isinko (-issino cos07/17 (C1-i) Sino casio S1828ticasoli 193 cos²o.1 i sino ti (1-1) smo cosol 0 W (ci-issino coso +18ing ticoso) I ts costot ishning + (i+1) sino cose . V2 [el-D) sin8l0s8 + icsin?eti costo) - -

T rios grisin 0+01+ D) Sino Cost Ici-) Sino COSE +ising - costo i irrroso i cose-tsing) + i sine (sinet (0587 Sven L cost Csino - coses + i sin ba sino-ceso) .. , _ rccos 0 + sino) (cosa tising 57 Va "Icsino-1056). Closo tisino) =>1933 = end elke 105€+sine 7 : V2 (sino-cosol =) In this the over all the phase factor, - In this output the foon of linearity poorized of the light at the polarized an angle 2 1x) = elp Contact --> where B = 15 an overall phase. polarized a linearly » the output is In the implies that light follows of angle is calculated - the polarization We have to get reosal): coser sing Istna ! Tsino-roso)

then the. Cos d = COS8+ Sino, sind = sino-coso - the ratio cwe get the Hand = cos > 1 above coscand sine is sub In sam Sino-coso cose + sino Land sino 2058 - ... sino ?: 7058 kano 17 Tos 14 smo COSE .. fano 1 [+ lang tant -fanti It tano tant tank = tanco-I) lineally Polaro as the showing the that the output is - 2ed and the polarization angle: