Need help pleaseHomework Answers
Given: mA= 40 kg , mB= 35 kg.
k= 0.25
and s=
0.2
Block A will move upwards only when block B will move forward.
Hence modeling this problem as forward moving of block B.
Friction force acting on block B , that will restrict to move :
Fs=s
[(mB.g sin15) + (mA.gsin15)]
= 0.2[ (35×9.81×sin15) + (40×9.81×sin15)]
= 0.2[88.87 + 101.56]
= 38.086 N
Fk= 0.25[88.87+101.56]
= 47.61 N
Force required to move , P = Fs+Fk = 38.086+47.61 = 85.7 N
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