What is the pH of a 0.22-M solutio of carbonic acid? (Ka = 4.2 x 10^-7)
Please explain, thank you.
[H+] = sqrt(Ka*C)
= sqrt(4.2*10^-7*0.22)
= 0.000304
pH = -log(H+)
= -log(0.000304)
= 3.52
What is the pH of a 0.22-M solutio of carbonic acid? (Ka = 4.2 x 10^-7)...
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