What is the temperature of 0.49 mol of gas at a pressure of 1.1 atm and a volume of 11.6 L ?

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Answer 1

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Answer #1

PV= nRT

P = Pressure in atm V= Volume in Liter

n = no of moles R = 0.0821 L atm K-1 Mol-1

T = Temperature in Kelvin

P = 1.1 atm V = 11.6 L n = 0.49 T = ?

Substitute the values and calculate Temperature

T = PV / nR = 1.1 x 11.6 / 0.49 x 0.0821 = 317.18 K

The temperature of the gas will be 317.18 K

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Answer 2

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