1 (15 pts) A block of mass m 2.10 kg slides with an initial speed v...
Question 12 of 14 > Final position A small block of mass m slides to the left on a frictionless, horizontal surface with speed u. Then, the block slides up a rough ramp that has an incline angle of 8. The coefficient of kinetic friction between the ramp and box is p. The acceleration due to gravity is g. Rough surface Initial position What is the height h of the block when its speed up the ramp equals nu, where...
As shown below (not to scale), a block of mass starts from rest
and slides down a frictionless ramp of height h. Upon reaching the
bottom of the ramp, it continues to slide across a flat
frictionless surface. It then crosses a "rough patch" on the
surface of length d=10m. This rough patch has a coefficient of
kinetic friction uK=.1. After crossing the rough patch, the block's
final speed is vf=2m/s. What is the height of the ramp? Hint: I...
A block of mass m -2.00 kg collides head on with a block of mass m- 10.0 kg initially at rest on a rough horizontal surface. The block m strikes m2 with a speed of 4.00 m/s. Immediately after the very brief inelastic collision, the 2.00 kg block bounces back with a speed of 1.20 m/s. Ignore the effect of friction during the collision. (a) 4pts.] Calculate the speed of the 10.0 kg block immediately after the collision. (b) 4...
3.0 kg block slides down a frictionless ramp of height 3.0
meters starting from rest. it then traverses a 2.0 metter rough
patch with a coefficient of kinetic friction 0.35 It then gets to a
smooth area where it compresses a horizontal spring of spring
constant 50 n/m.
Please help me Solve the rest of the physics problem
The answers to part A is x= 1.64 meters and part b is 1.58
meters
Problem 1 A 3.0 kg block slides...
A block of mass m is moving on a horizontal surface with speed v when it enters a rough patch and stops after traveling a distance L. What is the coefficient of kinetic friction between the block and the surface? O v2 /(29L) O v/ VgL O mv/(gL) O v2 /(L)
A m= 5.0 kg block slides on a flat, smooth track with an
initial speed of vi= 6 m/s. The block slides down a rough incline
that has a vertical height of h = 4 m onto another flat, smooth
track. The block’s final speed is vf= 10 m/s. How much energy is
lost to friction on the block as it slid down the incline?
An m 5.0 kg block slides on a flat, smooth track with an initial speed...
The figure(Figure 1) shows a 1.75-kg block at rest on a ramp of
height h. When the block is released, it slides without friction to
the bottom of the ramp, and then continues across a surface that is
frictionless except for a rough patch of width 10.0 cm that has a
coefficient of kinetic friction 0.650. Part A Find h such that the
block's speed after crossing the rough patch is 3.40 m/s .
A box with a mass of 8.67 kg slides up a ramp inclined at an angle of 28.3° with the horizontal. The initial speed is 1.66 m/s and the coefficient of kinetic friction between the block and the ramp is 0.48. Determine the distance the block slides before coming to rest. m As shown in the figure below, a box of mass m = 35.0 kg is sliding along a horizontal frictionless surface at a speed vi = 5.55 m/s...
As shown in the figure below, a 2.25-kg block is released from rest on a ramp of height h. When the block is released, it slides without friction to the bottom of the ramp, and then continues across a surface that is frictionless except for a rough patch of width 15.0 cm that has a coefficient of kinetic friction μk = 0.520. Find h such that the block's speed after crossing the rough patch is 4.20 m/s. An object with a...
A 2.10-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.10 m down the incline in 1.00 s. (a) Find the magnitude of the acceleration of the block. m/s2 (b) Find the coefficient of kinetic friction between block and plane. (c) Find the friction force acting on the block. magnitude N direction ---Select--- up the incline down the incline normal to the incline and upward normal to the incline and downward (d)...