Question

A wire carrying I = 1.5 A into the page is placed in the external magnetic field B = 0.8 T, that makes an angle 58 degree with the + y direction (as shown). What is the magnitude and direction of the magnetic force F_mag (with respect to the +x axis) on the wire, if the length of the wire segment immersed in the field is I = 0.7 m?

Answer 1

Magnetic force on a current carrying wire in a magnetic field is given by

$F = I(L*B) = ILBsin(\Theta ) = 1.5*0.7*0.8*sin(90^{0}) = 0.84 N$

This force will be perpendicular to both the Magnetic field and the current direction and according to right hand thumb rule, the force will be directed at 58⁰ with respect to +x axis.