Calculate the volume, in milliliters, occupied by 2.456 moles of nitrogen gas at a pressure of 1.55 atmosphere and a temperature of 327.91 Kelvin. Make sure to include the correct unit symbol with the answer.
Given:
P = 1.55 atm
n = 2.456 mol
T = 327.91 K
use:
P * V = n*R*T
1.55 atm * V = 2.456 mol* 0.08206 atm.L/mol.K * 327.91 K
V = 42.6366 L
V = 42637 mL
Answer: 42637 mL
Calculate the volume, in milliliters, occupied by 2.456 moles of nitrogen gas at a pressure of...
A
13.6 gram sample of argon gas has a volume of 813 milliliters at a
pressure of 2.80 atm. The temperature of the Ar gas sample is
_degrees celsius?
the
formula is PV=nRT
p=pressure
V=volume
n=moles
R=constant 0.08206
T=temperature in Kelvin
Temperature in Kelvin= degrees celsius +273
References Use the References to access important values if needed for this question. A 13.6 gram sample of argon gas has a volume of 813 milliliters at a pressure of 2.80 atm. The...
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