Calculate the volume occupied by 0.600 mol of nitrogen gas at 2.50 atm pressure and at...

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Question

Answer 1

Answer #1

Given

Moles of nitrogen gas = 0.600 mol

Temperature of nitrogen gas = 28 ⁰ C= 301 K

Pressure of nitrogen gas = 2.50 atm

We have relation, P V = n R T

where, P is a pressure of a gas, V is a volume of a gas, n is no. of moles of gas, R is a gas constant and T is temperature of gas.

On rearranging above equation , we get V =n R T / P

Therefore, Volume occupied by nitrogen gas =0.600 mol 0.082057 L atm mol ^-1 K ^-1 301 K / 2.50 atm

Volume occupied by nitrogen gas = 5.93 L

ANSWER : Volume occupied by Nitrogen gas = 5.93 L

Answer 2

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