1. h(a) = -a2-a
g(a) = 2a+1
Find (h-g)(-4)
2. f(n) = 2n +4
g(n) = 3n-1
Find (f+g)(-3)
Perform the indicated operation g(n)=2n-2 f(n)=n^2+1 FIND g(n)+f(n)
Which of the following series diverges? n +2 2n -1 n1 n+3 O A. 2 B. O C. 1,3 O D. 1, 2 OE. 2, 3 F. None O G. O H. 1,2,3 Find the sum of the series A. B. OC. 1/10 D. 1/2 3/2 3/4 OE. 1 F. 5/12 OG. 1/4 H. Divergent Which of the following series converges? oo 2n 1.Σ n 1 23n nE1 (n+ 1)3 n+ 1 3. O A. None O B. 2 O...
Use the definition of 0 to show that 5n^5 +4n^4 + 3n^3 + 2n^2 + n 0(n^5).Use the definition of 0 to show that 2n^2 - n+ 3 0(n^2).Let f,g,h : N 1R*. Use the definition of big-Oh to prove that if/(n) 6 0(g{n)) and g(n) 0(h{n)) then/(n) 0(/i(n)). You should use different letters for the constants (i.e. don't use c to denote the constant for each big-Oh).
Show that either g(n) = O(f(n)) or f(n) = O(g(n)) : 1. g(n) = n^2 +7n , f(n) = ^3 -2n^2 2. g(n) = 2n +4 , f(n) = 6lg(n^2)
For the reaction 3 H 2 (g)+ N 2 (g)⇌2N H 3 (g) at 225 ∘ C the equilibrium contant is 1.7× 10 2 . If the equilibrium mixture contains 0.14 M H 2 and 0.019 M N 2 , what is the molar concentration of NH 3 ?
Find a Maclaurin series for f(x). (Use (2n)! —for 1:3:5... (2n – 3).) 2"n!(2n-1) X Rx) = (* V1 +48 dt . -*** * 3 n = 2 Need Help? Read It Talk to a Tutor
Consider the sequence: {an = ln (2n? +n) – In(n? +10)}. (1) Give a, and a2 (2) Find algebraically (without using a calculator) the limit of the sequence if it exists. Show your work.
-) f(n)=n+1 g(n) = 3n² – 3 Find (fºg)(8)
Asymptotic notation O satisfies the transitive property i.e. if f(n)=O(g(n)) and g(n)=O(h(n)), then f(n)=O(h(n)). Now we know that 2n =O(2n-1), 2n-1 =O(2n-2?),....... , 2i=O(2i-1?),....... So using rule of transitivity, we can write 2n =O(2i-1?).We can go extending this, so that finally 2n =O(2k?), where k is constant.So we can write 2n =O(1?). Do you agree to what has been proved?If not,where is the fallacy? 6 marks (ALGORITHM ANALYSIS AND DESIGN based problem)
con re Find regene ra adius (3n)! (2n-2)! of (6x -9) n=1