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An 93.0 kg spacewalking astronaut pushes off a 640 kg satellite, exerting a 120 N force...

An 93.0 kg spacewalking astronaut pushes off a 640 kg satellite, exerting a 120 N force for the 0.540 s it takes him to straighten his arms. How far apart are the astronaut and the satellite after 1.00 min ?

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Answer #1

here,

mass of the satellite , m = 640 kg

force applied , F = 120 N

accelration , a = F/m

a = 0.1875 m/s^2

time of applied force , t = 0.54 s

final velocity after applied force , v = u + a*t

v = 0.10125 m/s

distance travelled when force is applied , s1 = 0.5 * a*t^2

s1 = 0.0273375 m

after 1 min , time t2 = 60 - t

t2 = 59.46 s

distance travelled in time t2 , s2 = v*t2

s2 = 6.02 m

the distance between the astronaut and the satellite after 1.00 min is (s1+s2)

the distance between the astronaut and the satellite after 1.00 min is 6.05 m

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