Question

ment Chapter 22, Problem 007 [ Your answer is partially correct. Try again. In the figure the four particles form a square of edge length a = 4.00 cm and have charges q1 8.11 nC, q2 = -18.8 nC, q3 = 18.8 nC, and q,--8.11 nC. What is the magnitude of the net electric field produced by the particles at the square's center? 91 42 dy Numb N/C or V/m The number of significant digits is set to 3; the tolerance is +/-2% The numm SHOW HINT LINK TO TEXT LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE MATH HELP

Answer 1

Positive X-axis is to right, Positive Y-axis is to upwards.
"Positive X-axis is to right, Positive Y-axis is to upwards. i is the unit vector along +ve X-axis and j is the unit vector along +ve Y-axis. Electric field at position r due to charge q_1 located at r_1 is E = 1/4 pi epsilon_0 q_1 (r - r_1)/
is the unit vector along +ve X-axis and is the unit vector along +ve Y-axis.

Electric field at position due to charge $q_1$ located at $vec{r}_1$   is $vec{E}=rac{1}{4piepsilon_0}rac{q_1(vec{r}-vec{r}_1)}{|vec{r}-vec{r}_1|^3}$

Four charges are $q_1=8.11,nC$ located at $vec{r}_1=ahat{j}=0.04,hat{j},m$ ,

   located at   ,

located at ,

$q_4=-8.11,nC$ located at   $vec{r}_4=0,m$

Center is located at

Net electric field at the center is $vec{E}=rac{1}{4piepsilon_0}rac{q_1(vec{r}-vec{r}_1)}{|vec{r}-vec{r}_1|^3}+rac{1}{4piepsilon_0}rac{q_2(vec{r}-vec{r}_2)}{|vec{r}-vec{r}_2|^3}+rac{1}{4piepsilon_0}rac{q_3(vec{r}-vec{r}_3)}{|vec{r}-vec{r}_3|^3}+rac{1}{4piepsilon_0}rac{q_4(vec{r}-vec{r}_4)}{|vec{r}-vec{r}_4|^3}$

Magnitude of electric field at the center of the square is $1.20*10^5,,N/C$ direction is along +ve Y-axis.