Question

A solution containing potassium bromide is mixed with one containing lead acetate to form a solution...

A solution containing potassium bromide is mixed with one containing lead acetate to form a solution that is 0.013 M in KBr and 0.0035 M in Pb(C2H3O2)2.

Will a precipitate form in the mixed solution? If so, identify the precipitate.

Express your answer as a chemical formula. Enter noreaction if no precipitate is formed.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ksp of PbBr2 can be wriiten as below

7.9 X 10-5= [Pb2+][Br-]2

[Pb2+] = 0.0035M, [Br-] = 0.013M

If we Substitute those values in the equation

[Pb2+][Br-]2  will give

0.0035*0.013*0.013 = 5.915 X10-7


The resulting value is lesser than the Ksp, Hence no precipitate of PbBr2 will be produced.

Add a comment
Know the answer?
Add Answer to:
A solution containing potassium bromide is mixed with one containing lead acetate to form a solution...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A solution containing sodium fluoride is mixed with one containing calcium nitrate to form a solution...

    A solution containing sodium fluoride is mixed with one containing calcium nitrate to form a solution that is 0.015 M in NaF and 0.010 M in Ca(NO3)2 Will a precipitate form in the mixed solution? If so, identify the precipitate. Express your answer as a chemical formula. Enter noreaction if no precipitate is formed. Submit Request Answer

  • 3. A solution containing potassium bromide is mixed with one containing strontium nitrate to form a...

    3. A solution containing potassium bromide is mixed with one containing strontium nitrate to form a solution that is 0.0044 M in KF and 2.1x 10-4 M in Sr(NO3)2. The Ksp for Sifz is 7.9 x 10-10 Does a precipitate form in the mixed solution? If so, identify the precipitate a. Find the precipitate using double replacement reaction. b. Write the chemical equation for the formation of the precipitate omitting the spectator ions: c. Write the following: Chemical Equation: Ksp...

  • Determine whether a precipitate form in the following reaction conditions: a. A solution containing lead (II)...

    Determine whether a precipitate form in the following reaction conditions: a. A solution containing lead (II) nitrate is mixed with one containing sodium bromide to form a solution that is 0.0150 M in Pb(NO3)2 and 0.00350 M in NaBr. Does a precipitate form in the newly mixed solution? Ksp PbBr2 = 4.67 x 10-6 . b. A solution containing iron (II) nitrate is mixed with one containing sodium phosphate to form a solution that is 0.0365 M in Fe(NO3)2 and...

  • solution A solution B Does a precipitate form when A and B are mixed? empirical formula...

    solution A solution B Does a precipitate form when A and B are mixed? empirical formula of precipitate ammonium nitrate sodium acetate O yes no silver nitrate potassium bromide yes no manganese(II) bromide zinc nitrate yes no

  • A 55.5 mL sample of a 0.106 M potassium sulfate solution is mixed with 40.0 mL...

    A 55.5 mL sample of a 0.106 M potassium sulfate solution is mixed with 40.0 mL of a 0.106 MM lead(II) acetate solution and the following precipitation reaction occurs: K2SO4(aq)+Pb(C2H3O2)2(aq)→2KC2H3O2(aq)+PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 0.991 g . Part (A) Identify the limiting reactant. 1. PbSO4 2. KC2H3O2 3. Pb(C2H3O2)2 4. K2SO4 Part (B) Determine the theoretical yield. mass of PbSO4 = __________ g Part (C) Determine the percent yield. ____________ %

  • When a solution of potassium iodide is mixed with a solution of lead nitrate, a bright...

    When a solution of potassium iodide is mixed with a solution of lead nitrate, a bright yellow solid precipitate forms Calculate the mass of the solid produced (molar mass = 461 g/mol) when starting with a solution containing 242.36 g of potassium iodide (molar mass = 166 g/mol), assuming that the reaction goes to completion. Give your answer to three significant figures 2KI (aq) Pb(NO3)2 (aq) » Pbl2 (s) 2KNO3 () g

  • An aqueous solution containing 5.65 g of lead(II) nitrate is added to an aqueous solution containing...

    An aqueous solution containing 5.65 g of lead(II) nitrate is added to an aqueous solution containing 6.26 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: What is the limiting reactant? O potassium chloride lead(II) nitrate The percent yield for the reaction is 81.4%. How many grams of the precipitate are formed? precipitate formed: How many grams of the excess reactant remain? excess reactant remaining:

  • Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipi...

    Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will form, enter its empirical formula in the last column. solution A solution B Does a precipitate form when A and Bare mixed? empirical formula of precipitate x 6 ? cadmium acetate manganese(II) bromide O yes no potassium sulfide iron(II) nitrate O yes no ammonium bromide potassium acetate O yes no

  • 65.0 mL sample of a 0.102 M potassium sulfate solution is mixed with 38.5 mL of...

    65.0 mL sample of a 0.102 M potassium sulfate solution is mixed with 38.5 mL of a 0.122 M lead(II) acetate solution and the following precipitation reaction occurs: K2SO4(aq)+Pb(C2H3O2)2(aq)→2KC2H3O2(aq)+PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 0.993 g . a. Define the theoretical yield b. Define the percent yield.

  • An aqueous solution containing 8.16 g of lead(II) nitrate is added to an aqueous solution containing...

    An aqueous solution containing 8.16 g of lead(II) nitrate is added to an aqueous solution containing 6.57 g of potassium chloride. Enter the balanced chemical equation for this reaction. Be sure to include all physical states. balanced chemical equation: Pb(NO3)2(aq) + 2 KCl(aq) + PbCl,(s) + 2 KNO3(aq) What is the limiting reactant? O potassium chloride lead(II) nitrate The percent yield for the reaction is 91.6%. How many grams of precipitate is recovered? precipitate recovered: How many grams of the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT