Question

1)

Given two capacitors with capacitances C1 > C2. If they store the same amount of charge, which one will store more energy? If the two capacitors have the same potential difference across them, which one will store more energy? Two 2.0 cm x 2.0 cm square aluminum electrodes, spaced 0.50 mm apart in a vacuum, are connected to a 100 V battery. What is the capacitance? What is the charge on the positive electrode?

2)

Answer 1

Answer 2

1. if they have same charge, Energy is inversely proportional to capacitance

therfore

Answer 3

1 a

Q =CV

V=Q/C

since C1>C2

so V2>V1

we know energy E = 1/2 CV^2 = QV/2

so E2>E1

b we know energy E = 1/2 CV^2

since both have same potential difference and C1> C2

so E1>E2

2 a

C=eA/d

= 8.85e-12*0.02^2/0.5e-03

=7.08e-12 F

b Q=CV = 7.08e-12*100 = 1.08e-10 C

Answer 4

1.a)since E =Q^2/2C so the C2 capacitor will have more energy as E INversely proportional to C.

B)ALSO E=0.5*C*V^2 as V is same so the C1 will have more energy as it has more capacitance.

2.C=epsilon.A/d =8.854*10^-12*2*2*10^-4/0.5*10^-3 = 7.08 *10^-12

b) Q =CV = 70.83 nC

Answer 5

C=QV

E= CV*V/2

C1 > C2

Q= Constant.

C1/V1 = C2/V2    === > C1 = C2 V1 /V2           

Then V1 is Less and V2 is Hig

E= C*V*V/2

Example

E1/E2   = C1 V1 V1/C2 V2 V2

                Q= 6 , C1 = 6 , V1 = 1 , C2 = 3 , V2 = 2

Apply E1/E2 = 6 *1 *1 / 3 * 2 * 2

                E1/E2 =