Question

Physics help. Thanks!

When the output voltage is measured across the capacitor (between the open terminals) in the circuit below, this circuit acts like a filter. a) Derive an expression for Vout/Vin as a function of angular frequency of the source. b) Show how this circuit behaves in the limit w + . c) Show how this circuit behaves in the limit w +0. d) Given this information, what kind of filter is this? Figure 1: A simple R-L-C filter.

Answer 1

I Ans. (a) Let w be angular frequency of source. Inductive rectance 1 X = WL tell me Capacitive rectance X = 1 WC Current in circuit I - V ✓ R² + (x2 - Xc) 2 VR: #(001 - the ja R2

Vout = Voltage across Capacitor cross Ixc we VR? + (LOL – Vlwc)? Vin=v Vout - /we Vin R2 + (WL-!

1/wc v R2 + (WL -lc)? ✓ R?W? (² + w²c2 (LOL - 1/ ² For w a ✓ R²w² (² + (W²LC - 12 Vout to Vin Vout to

(C) For w to Vendo tot loje es ( Vout - Vin As for high frequencies out put voltage is zero and for low frequencies out put Voltage is equal to input voltage % іt bеhаvе a gоо ол. Т я іt. Балдау lower frequencies,

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