Homework Answers
Number of samples = 10
Sum of number of faliures = 8+23+6+10+12+14+9+11+29+12 = 134
C-bar = Sum of number of complaints/number of samples = 134/10 = 13.4
For 3 sigma control limit value of Z = 3
Upper specification limit = C-bar + [Z(√C-bar) ]= [13.4+(3 x √13.4)] = 13.4+(3×3.66) = 13.4+10.98 = 24.38
Lower specification limit = C-bar - [Z (√C-bar) ] = 13.4- [3(√13.4)] = 13.4-(3x3.66) = 13.4-10.98 = 2.42
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