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please ahow all work What will be the steady-state effluent BOD concentration for a CSTR (complete...
Problem 2. An activated sludge unit is being designed to treat 375,000 gpd with an influent BOD of 250 mg/1. Parameters for the wastewater are: Y 0.6, m -2.0 days-1, kd0.15 days-1 and K, 40 mg/l. The recycle flow is 3750 gpd with a biomass concentration of 50 X, where X is the reactor biomass concentration. The waste sludge flow is 500 gpd. Calculate the mean cell residence time, e, and CSTR volume required for a 95% removal of influent...
\The flow rate to treat is 5.6 MGD and the BOD concentration is 150 mg/L. The design solids concentration (X) at steady-state is 2,000 mg/L. The design MCRT is 7 days. The kinetic coefficients are as follows: k = 2 g BOD/g cells*day; Ks = 25 mg BOD/L; kd = 0.06 1/day; Y = 0.5 g cells/g BOD. The influent ammonia concentration is 40 mg/L and nitrification is needed. It takes 1400 ft3 of air per pound of BOD. Use...
You are designing a sewage lagoon to accommodate an input flow of 0.1 m3/min. At steady-state, the effluent (also at 0.1 m3/min) from the lagoon must not exceed a BOD of 10 mg/L. Assume the lagoon is well mixed, that there are no additional inputs to the lagoon and that the BOD degrades with a reaction rate constant equal to 0.1 day-1. What is the volume of the lagoon needed to achieve the effluent BOD goal if the influent BOD...
Question 2 A complete mix activated sludge process is to be used for biological treatment. Assume the following for the activated sludge process: • Plant influent BODs of 156 mg/L • Sludge age is 8 days Biomass yield (Y) of 0.54 kg biomass / kg BOD • Endogenous decay rate (kd) = 0.05 day! • Ks=10 g BOD/m3 Biomass concentration (X) of 2700 mg/L • recycle biomass concentration (Xr) of 12,000 mg/L The fresh flow rate treated is 1000 m²/day...
5. A disinfection process destroys E.coli in water. The influent concentration of coliform is 120 coliforms/mL. If the reactor volume is 500 L and flow is 1600 L/day then what is the effluent concentration of coliform per liter. Assume the reactor is at steady state with a reaction rate constant of 0.75 day!. (15 points)
A wastewater flow of 18,000 m3/day is to be treated in a completely mixed activated sludge system at a concentration of 3000 mg/L MLSS (mixed liquor suspended solids). The secondary clarifier is designed to thicken the sludge to 12,000 mg/L. Assuming a growth yield coefficient of 0.5 Kg/Kg, an influent BOD of 100 mg/L with a residence time of 8 days, determine the following: a) The volume of the reactor b) The mass of the solids and the wet volume...
3. Determine the aeration tank volume (mgd), excess biomass in the waste sludge (kg/d), and the BOD f a completely mixed activated-sludge process by assuming the following: k 4.0 day r-0.55 lb vSS/1b BOD, K, 80 mg/l, ks-0.05 day', wastewater flow rate 2.5 mgd, soluble effluent BOD- 15 mgl, soluble influent BOD - 170 mgl, and MLVSS-2200 mg/l, and mean cell residence time -6 days. (15 pts) 3. Determine the aeration tank volume (mgd), excess biomass in the waste sludge...
If the note growth rate of microorganisms is r'g, write a steady-state biomass balance equation for the complete mixed biological reactor (aeration tank) shown in the figure below. If the influent Q = 0.150m3/s and BOD5 = 84 mg/L, volume of the reactor V = 970 m3, and MLVSS concentration X = 2000 mg/L, determine the F/M ratio. balance equation for the 9. a) If the net growth rate of microorganisms isr'g, write a steady-state biomass complete mixed biological reactor...
7. You work for the Ministry of Environment to evaluate the maximum ultimate BOD concentration in the effluent of a new wastewater treatment plant such that the oxygen deficit never exceeds 1.5 mg/L in the receiving river. During dry weather (i.e., lowest river flow), the wastewater will be diluted 10 times in the river water and the river water contains 3.5 mg/L of ultimate BOD. Also during dry weather, you know that the river velocity after the wastewater discharge would...
Situation (note: Problem 2 is not linked with Problem 1): Assuming the design flow rate of raw wastewater to be treated is 20 MGD in the design year, the dissolved BODs is 380 mg/L, and SS is 360 mg/L. The wastewater generated by the sludge treatment process is about 4 MGD with the dissolved BODs being 1800 mg/L, and SS being 1200 mg/L, and will be returned to the wet well in the pumping station at the beginning of the...