Question

1. Researchers want to examine the effect of scent on memory. A total of 9 people were recruited for the study. Each person randomly assigned to one of the three experimental groups. Each person was asked to read a passage from a book. A week later, each study participant was asked to recall as much information as they could from the previously read passage.  Researchers determined a score for each subject representing the facts that have been correctly recalled. The data are available in Table 1.

Group 1: Scent is present during a passage reading and during the passage recall

Group 2: No scent is present in either the passage reading or the passage recall

Group 3: Scent is present during the passage reading only

The purpose of this study is to identify whether there are differences between the mean number of facts recalled by the experimental group one week after reading the original passage (α = 0.05).

For this question, conduct a one-way ANOVA by hand (showing all your calculations) to compare the means of these three samples. Remember to follow the steps of hypothesis testing and show your calculations. Also, create a one-way ANOVA summary table showing your results of the analysis (see table 2 for an example).

Table 1.

Passage recall scores by group, individual group means, and overall mean.

Group 1(=3)	Group 2(=3)	Group 3(=3)
22	30	27
33	20	18
29	14	17
	(N=9)

Answer 1

Solution from the given information, we have following table shows the group total: Gi G2 G3 30 29 27 18 33 20 17 14 84 Total 62 64 following table shows the groud total and total of square values! G² G 22 33 484 1089 841 900 29 30 yoo lu 196 27 18 17 210 1729 329 289 5252 Total from above table EG=8u, EG==64. EG3=62, n = 3, 22=3, 03 =3, EG=210 E6²=5252

Now SS7 = EG² (EG)? = 352.00 N EGITEGO EG377 (EG) SSBetwear t 98.67 ni no ng N NOW - SST-SS Between SS 2253.33 so we have k23. ::SS within Since there are 3 different groups Therefore degree of freedoms are! dictuen Kr=3-1=2 df within a N-629-3=6 = 6+2=8 deftotal Now =49.333 SS betuary Ms between diffetween SS within Ms within If within 튼 =42.222 ftest statistics as MS between =hl7 MS within The critical value of fusing excel function - FINC.05.2015 5.143

Since F25.143 e reject the null hypothesis. There as no evidence to conclude that there are difference between the mean number of facts recalled by the experimental group are one week after reading the original passage. following is the completed A Nova. ANOVA Table Source SS Treatment 98.67 2 149.333 (1-17 Error [253.83 42.222 Total Idf | MS 12. 6 352.00 1 8 *please ratet