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of elasticity (E.) Per ACI 318-14 code, determine the modulus of rupture (f) and modulus of elasticity (Ec) for concrete with a compressive strength of 3,500 psi. Assume the concrete is normal weight concrete. 2.

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Answer #1

a) Modulus of elasticity = 57000\sqrt{f_{ck}}

= 57000 * sqrt ( 3500)

=3372165 psi

b) Tensile strength = 7.5\sqrt{f_{ck}}

=7.5*sqrt(3500)

=443.7 psi

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