Question

1-) In the pipe bundle lined up from steel pipes with outer diameters 1.8 cm, the number of rows of pipes perpendicular to the flow is 7 and the row spacing is St = 6 cm, the number of pipe rows in the flow direction is 7 and the row spacing is SL = 6 cm. In case the outer surface temperature of the pipes remains constant at 120 oC and water enters at 0.9 m / s velocity 46 oC perpendicular to the pipe bundle. outer surface average heat transfer coefficient calculation

note: please write clearly and understandably and tell

Answer 1

Ts = 120°C Water о ооооо Veoanfrec Оооооо ТЕ - 46°C оооооо ооооооо – об ОО ООО So 0 0 0 0 ООО to oo ooo SL .. toline Arrangement of tubes

let mean =41855 > 3 TS 1-44 V - Reo temperature of water is 60 °C Porferlies at this temperature K-0.654 w 8-983.3 kg 0.467 103 kg Po-3.99 Too In line aswangement Vinex - Sr 6 x0.9 = 129 msec Sr-o PVD-985,3% 1199x18x16? le 0467X163 Reo 48891-98 0:25 0.27 Red () 163 0.27 432.66 This Musselt to is applicable for the 16 to our Cases M = 4 4 cosesfordong covechen fochis F= 0.96 a f = 432.66X0.96-415:36 theo 0.63 0:56 و { - HUD ALLIE Huoneis XX - 41536x0.654 1.8x102 th 15091.24 ur As - NIDL= 496 x 1.8x10²x 1 = 2.77 BY HT SIL-985320-94 4x6x6 * = 9H-C0g Te TE-(ST: Se = 1960-190-46) 33405 Te = 44-46

to assume Tom-Titte - 46+4 796 = 46.980 which is not close 60°C so we do calculation agoch Assume Tom - 47° C Properties of wales at 4700 8-989.3 kg K=0.640 W p=4180.45 le 0.576x103 kg m3 2 38 Podare 6-1.3 Reo Nup = 0.27 (39881165 Vmax ST V = 6 x0.9 = 1.29 m/sec ST-O Vimax a 989.3 x 1.99x18x10 - 39881-16 0-576x103 they = 0.27 Reorts Ros (3) -90095 94 (39881161983 (347944 (****) Nuo 438.35 This, Hussel No is applicable for e 16 but de Our lese dhe = 7 So correction factost = 0.96 -0.96% 438.35 = 480.82 h MODNI LIGXK 420-82X0-640 - 14962-49 1.8810² IL- Outer Surface heat 14962149 w MODALLIG Fxrup m2 transfer Coeff